If the second date or time is earlier than the first date or time, the result is negative. If the second date or time is later than the first date or time, the result is positive. The expressions must both contain the specified date or time part. I would like to calculate number of days between two dates in redshift but the function should take into account the time that's mean day0 if there is less than 24 hours between the dates like Timestampdiff function in MySQL. If you are finding the difference in hours between two timestamps, 8:30:00 and 10:00:00, the result is 2 hours.ĭate|time|timetz|timestamp: A DATE, TIME, TIMETZ, or TIMESTAMP column or expressions that implicitly convert to a DATE, TIME, TIMETZ, or TIMESTAMP. we were trying to find the min max and avg of the ltrim-dateadd-datediff and it was too expensive on 300 million rows to be useful even as a one-off solution. If you are finding the difference in hours between two timestamps, 01-01-2009 8:30:00 and 01-01-2009 10:00:00, the result is 2 hours. this seems neat, i did find that is was less performant than our needs required. In this case, the function returns 1 year despite the fact that these dates are only one day apart. Let’s look at the syntax, examples, and use cases of Redshift DATEDIFF function: Redshift DATEDIFF. For example, suppose that you're calculating the difference in years between two dates, 12-31-2008 and 01-01-2009. The Redshift DATEDIFF function is used to calculate the difference between two date values based on the interval specified using either Years, Months, Days, Weeks, Hours, Minutes, Seconds, Milliseconds, et al. Specifically, DATEDIFF determines the number of date part boundaries that are crossed between two expressions.For more information, see Date parts for date or timestamp functions. Got it :) datex > DATE (dateadd (DAY,-7, currentdate)) SELECT x.datex, Signups, Pageload FROM (SELECT CAST (mpdate AS DATE) AS datex, mpeventname, COUNT (DISTINCT mpdeviceid) AS Signups FROM mpmasterevent WHERE mpeventname 'emailpagesubmit' AND datex > DATE (dateadd (DAY,-7, currentdate)) GROUP BY mp. The Redshift DATEDIFF function is used to calculate the difference between two date values based on the interval specified using either Years, Months, Days. Again, the expected results would be a value of 1.15 between 2 values that are 1 year, 1 month and 15 days apart. select, cast ( (cast (begindate as date) - cast (enddate as date) YEAR) as decimal (3,2)) AS yeardiff from x. Checking the docs for Amazon Redshift shows this: DATEDIFF ( datepart, )ĭatepart: The specific part of the date or time value (year, month, or day, hour, minute, second, millisecond, or microsecond) that the function operates on. Currently, my code just returns zero on the right side of the decimal place.
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